A parallel plate capacitor is filled with dielectrics as shown in Fig. What is its capacitance ?

Answer

`(2in_(0) A K_(1) K_(2))/(d(K_(1) + K_(2))`

Explanation

The arrangemnt shown in Fig, is equivalent to two condensers of capacities `C_(1)` and `C_(2)`, connected in series, where
`C_(1) = (in_(0) AK_(1))/(d//2) = (2 in_(0) AK_(1))/(d)`
`C_(2) = (in_(0) AK_(2))/(d//2) = (2 in_(0) AK_(2))/(d)`
Use `(1)/(C_(s)) = (1)/(C_(1)) + (1)/(C_(2))`