five charge `q_(1),q_(2),q_(3),q_(4)`and `q_(5)` are fixed at their positions as shown in figure .`s` is Gaussian surface .The Gauss's law is given by `ointvec(E).vec(ds)=(q)/(epsilon_(0))`

Which of the following statement is correct?

Options

A. `E` on the LHS of the above equation will have a contribution from `q_(1), q_(5)` and `q_(3)` while `q` on the RHS will have a contribution from `q_(2)` and `q_(4)` only
B. `E` on the LHS of the above equation will have a contribution from all charges while `q` on the RHS will have a contribution from `q_(2)` and `q_(4)` only
C. `E` on the LHS of the above equation will have a contribution from all charges while `q` on the RHS will have a contribution from `q_(1), `q_(3)` and `q_(5)` only
D. Both, `E` on the LHS and `q` on the RHS will have contribution from q_(2)` and `q_(4)` only

Answer

B

Explanation

According to Gauss's theorem in electrostatics, `oint vec(E). Vec(ds) = (q)/(in_(0))`, Here `vec(E)` is due to all the charges `q_(1), q_(2), q_(3), q_(4)` and `q_(5)`. As `q` is closed by the Gassian surface, therefore, `q = q_(2) + q_(4)`. Choice (b) is correct.