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A thin conducting ring orf radius R is g...

A thin conducting ring orf radius `R` is given a chareg `+Q`, Fig. The electric field at the centre `O` of the ring due to the charge on the part `AKB` of the ring is `E`. The electric field at the centre due to the charge on part `ACDB` of the ring is

A

`3 E` along `KO`

B

`E` along `OK`

C

`E` along `KO`

D

`3E` along `OK`

Text Solution

Verified by Experts

The correct Answer is:
B
Charge on part `AKB = Q//4`, Fig
`:. E` at O due to `AKB` is due to charge `Q//4`.
In the part `ACDB`, intensity at `O` due to charges on `AC` and `DB` cancels out. Net intensity at `O` is due to charge `Q//4` on part `CD`. Its value must be `E` along OK.
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Knowledge Check

  • A thin conducting ring of radius R is given a charge +Q , Fig. The electric field at the center O of the ring due to the charge on the part AKB of the ring is E . The electric field at the center due to the charge on part ACDB of the ring is

    A
    `3 E` along `KO`
    B
    `E` along `OK`
    C
    `E` along `KO`
    D
    `3E` along `OK`

  • A thin conducting ring of radius R is given a charge +Q. The electric field at the centre O of the ring due to the charge on the part ABCD of the ring is

    A
    3E along KO
    B
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    C
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    D
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    A
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    B
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    `(q)/(4piepsilon_(0)R^(2))`
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    `(q)/(2piepsilon_(0)R^(2))`

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