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Let P(r)=(Q)/(piR^4)r be the charge dens...

Let `P(r)=(Q)/(piR^4)r` be the charge density distribution for a solid sphere of radius R and total charge Q. For a point 'p' inside the sphere at distance `r_1` from the centre of the sphere, the magnitude of electric field is:

A

`(Q)/(4pi in_(0) r_(1)^(2))`

B

`(Q r_(1)^(2))/(4pi in_(0)R^(4))`

C

`(Q r_(1)^(2))/(3n pi in_(0) R^(4))`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C

In Fig, dotted sphere of radius `r_(1)` is the Gaussaian surface.According to Gauss's theroem,

`oint vec(E).d vec(s) = (q_(inside))/(in_(0))`
`E ds cos 0^(@) = (1)/(in_(0)) rho (r ) xx dV`
`E (4pi r_(1)^(2)) xx1 = (Q r_(1))/(in_(0) pi R^(4)) ((4)/(3) pi r_(1)^(3))`
`E = (Q. 4 pi r_(1)^(4))/(3in_(0) pi R^(4) (4pi r_(1)^(2))) = (Q r_(1)^(2))/(3pi in_(0) R^(4))`
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