In Fig, `E =5` volt , `r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega` and `C = 3 muF`. Then the numbercal value of the charge on each plate of the capacitor is

Options

A. `24 muC`
B. `12 muC`
C. `6 muC`
D. `3 muC`

Answer

C

Explanation

As is clear from Fig, current will flow only through the branch cantaining `R_(2)`.
`I = (E)/(R^(2) + r) = (5)/(4+1) = 1 amp`.
pot diff across `R_(2)` ,
`V = IR_(2) = 1xx4 = 4 V`
If `q` is charge on each capacitor then
`(q)/(C ) + (q)/(C ) = 4`
`(2q)/(C ) = 4, q = 2 C = 2xx3 = 6 muC`