A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved farther apart by means of insulating handles:

Options

A. the stored energy of the capacitor increases
B. charge on capacitor increases
C. voltage of the capacitor increasess
D. the capacitance increases

Answer

A, C

Explanation

As, `Q` reamains constant after disconnecting the battery , `C = (in_(0) A)/(d)` decreases, as `d` increases, As `Q` is constant `C_(i) V_(i) = C_(f) V_(f)`
`C_(f) lt C_(i)` So `V_(f) gt V_(i)`
so voltage increases
As `U = (1)/(2) QV, U prop V`, So `U_(f) gt U_(i)` as `V_(f) gt V_(i)`