What is the length of a nichrome wire of radius 0.32 mm, resistance `9.3 Omega` and resistivity `15 xx 10^(-6)Omega m` ? If a potnetial differences of 10 V is applied across the wire, what will be the current in the wire ?
Text Solution
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Here, `l =?, r = 0.32xx10^(-3) xx 10^(-3) m, R =9.3 Omega , rho = 15xx10^(-6)Omega m, V= 10V` `R=(rho l) /(pi r^(2))` or `l = ((9.3)xx3.14 xx (0.32 xx 10^(-3))^(2))/ ((15xx10^(-6))) = 0.199 m ~= 0.20m` Current `I=V/R = 10/9.3 = 1.075= 1.08 A`
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