In a Wheatstone bridge circuit, `P=5 Omega, Q=6 Omega, R=10 Omega` and `S= 5 Omega`. Find the additional resistance to be used in series with S, so that the bridge is balanced.

Explanation

To solve the problem of finding the additional resistance \( X \) to be used in series with \( S \) in a Wheatstone bridge circuit, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Wheatstone Bridge Condition**:
The Wheatstone bridge is balanced when the ratio of the resistances in one branch is equal to the ratio of the resistances in the other branch. The condition for balance can be expressed as:
\[
\frac{S + X}{R} = \frac{Q}{P}
...