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If 0.8 mole of electrons flow through a ...

If 0.8 mole of electrons flow through a wire in 55 minutes. What is (a) the total charge in kilocoulomb that passes through the wire and (b) the magnitude of the current? Avogadro's number `=6xx10^(23)` per mole.

Text Solution

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No. of electrons in 0.8 mole, `N=0.8 xx 6xx10^(23)`
(a) Charge flowing
`q=Ne=(0.8 xx 6 xx 10^(23)) xx (1.6xx10^(-19))C`
`=7.68xx10^(4)C=76.8 xx 10^(3) C`
= 76.8 kilo coulomb
(b) Current `=q/t=76.8 xx 10^(3)C/(55xx60)s = 23.3 A`
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