In a conductor, `10^(16)` electrons move from a point A towards point B in 1 milli second. `10^(14)` positive ions move from a point B towards point A in 1 milli second. What is the current in ampere and its direction? Charge on electron = charge on position ion `= 1.6 xx 10^(-19)C`.

Explanation

Here, `n_(e)=10^(16) , n_("ion")=10^(14) , t=10^(-3)s`,
Charge on electron or ion, `q=1.6xx10^(-19)C`.
Current, `I=(n_(e) xx q +n_("ion")xxq)/(t)`
`(10^(16)xx1.6xx10^(-19)+10^(14)xx1.6xx 10^(-19))/(10^(-3))`
`=(10^(16)xx1.6xx10^(-19))/(10^(-3)) =1.6A`
The direction of current is from B to A.