A current of 3 A is flowing through a wire of length 2 m and cross- sectional area `1mm^(2)`. If wire contains `10^(29) "electrons"//m^(3)`, calculate the average time taken by an electron to cross the length of the wire.
Text Solution
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To solve the problem step by step, we will calculate the average time taken by an electron to cross the length of the wire using the given parameters.
### Step 1: Understand the parameters given in the problem
- Current (I) = 3 A
- Length of the wire (L) = 2 m
- Cross-sectional area (A) = 1 mm² = \(1 \times 10^{-6}\) m²
- Number density of electrons (N) = \(10^{29}\) electrons/m³
- Charge of an electron (e) = \(1.6 \times 10^{-19}\) C
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