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There is a copper wire of length 2.2 m, ...

There is a copper wire of length 2.2 m, of area of cross-section 2.0sq.mm, carrying a current of 6.0A. If the number density of electrons in copper is `8.5 xx10^(28) m^(-3)`, find the time taken by an electron to drift from one end to another end of the wire.

Text Solution

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Here, `l =2.2m` ,
`A=2.0 sq. mm =2xx10^(-6) sq.m`,
`I=6A , n=8.5xx10^(28)m^(-3)`
Drift velocity, `v_(d) =I/(n A e)`
`6/((8.5xx10^(28))xx (2xx10^(-6))xx(1.6xx10^(-19)))`
`=2.2xx10^(-4) ms^(-1)`
Time of drifting the electron,
`t=l/v_(d) =(2.2)/(2.2xx10^(-4))=10^(4)s`
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