Find the current flowing through a copper wire of length 0.2m, area of cross-section `1 mm^(2)`, when connected to a battery of 4 V. Given that electron mobility `=4.5xx10^(-6) m^(2)V^(-1) s^(-1)` and charge on electron `=1.6xx10^(-19)C`. The number density of electron in copper is `8.5 xx10^(28) m^(-3)`.

Explanation

To find the current flowing through the copper wire, we can follow these steps:

### Step 1: Convert the area of cross-section from mm² to m²
The area of cross-section is given as \(1 \, \text{mm}^2\). We need to convert this to square meters:
\[ 1 \, \text{mm}^2 = 1 \times 10^{-6} \, \text{m}^2 \]

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