Calculate the resistivity of the material of a wire 1.0 m long, 0.4 mm diameter and having a resistance of `2.0 Omega`.
Text Solution
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Here, `l=1.0m` , `D=0.4 mm =0.4 xx10^(-3) m, R=2.0 Omega` `rho = (RA)/(l) = (R pi D^(2))/4l= (2.0xx(22//7)(0.4xx10^(-3))^(2))/(4xx1.0)` `=2.51 xx10^(-7) Omega m`
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