A wire has a resistance of `16 Omega`. It is melted and drawn into a wire of half its length. Calculate the resistance of new wire. What is the percentage change in its resistance?
Text Solution
AI Generated Solution
To solve the problem, let's break it down into steps:
1. **Given Data:**
- Initial resistance, \( R = 16 \Omega \)
- The wire is melted and drawn into a wire of half its original length.
2. **Concepts Involved:**
- Resistance \( R \) of a wire is given by the formula:
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Knowledge Check
A wire has a resistance of 32Omega . It is melted and drawn into a wire of half of its original length. What is the resistance of the new wire?
A
`32Omega`
B
`16Omega`
C
`8Omega`
D
`4Omega`
If a wire of length I has a resistance of R, is stretched by 25 %. The percentage change in its resistance is ?
A
`25 %`
B
`50 %`
C
`45.5 %`
D
`56.25 %`
A 5Omega resistance wire is doubled on it. Calculate the new resistance of the wire.
A
`1.25Omega`
B
`2.25Omega`
C
`1.5Omega`
D
`1.00Omega`
PRADEEP-CURRENT ELECTRICITY-Problems for Practice (B)
