The external diameter of a 4 m long hollow tube is 10 cm and thickness of its wall is 5 mm. If the specific resistance of the copper is `1.7xx10^(-8)Omega m`, then calculate its resistance.
Text Solution
AI Generated Solution
To calculate the resistance of the hollow copper tube, we will follow these steps:
### Step 1: Identify the given values
- Length of the tube (L) = 4 m
- External diameter (D) = 10 cm = 0.1 m
- Thickness of the wall (t) = 5 mm = 0.005 m
- Specific resistance (ρ) = \(1.7 \times 10^{-8} \, \Omega \, m\)
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