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Two conductors of conductnaces G(1) and ...

Two conductors of conductnaces `G_(1)` and `G_(2)` are connected in series. They are connected in parallel to another conductor of conductance `G_(3)`. Determine their equivalent conductance.

Text Solution

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Let `R_(1),R_(2)` and `R_(3)` be the resistances of conductors of conductances `G_(1),G_(2)` and `G_(3)` respectively.
Here `R_(1)=1/G_(1),R_(2)=1/G_(2),R_(3)=1/G_(3)` The effective resistance between A to B is

`R=(R_(3) xx (R_(1) +R_(2)))/(R_(3)+(R_(1) +R_(2)))`
`:.` Effective conductance,
`G=1/R = (R_(3) +(R_(1) +R_(2)))/(R_(3)xx(R_(1) +R_(2)))`
`:. G =(1/(G^(3)) + 1/(G_(1)) +1/(G_(2)))/(1/(G_(3))xx(1/(G_(1)) +1/(G_(2))))`
`(G_(1)G_(2) +G_(2)G_(3) +G_(1)G_(3))/((G_(2) +G_(1)))`
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