The resistance of two conductors in series is `40 Omega` and their resistance becomes `6.4 Omega`, when connected in parallel. Find the resistance of individual conductors.
Text Solution
AI Generated Solution
To find the resistance of the individual conductors, we can follow these steps:
### Step 1: Define the resistances
Let the resistance of the first conductor be \( R_1 \) and the resistance of the second conductor be \( R_2 \).
### Step 2: Set up the equations
From the problem, we know:
1. The total resistance in series is given by:
...
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