A resistor of `5 Omega` is connected in series with a parallel combination of a number of resistors each of `5 Omega`. If the total resistance of the combination is `6 Omega` , how many resistor are in parallel?
Text Solution
AI Generated Solution
To solve the problem step by step, we can follow these instructions:
### Step 1: Understand the Configuration
We have a resistor of \(5 \, \Omega\) in series with a parallel combination of \(n\) resistors, each of \(5 \, \Omega\). We need to find the value of \(n\) given that the total resistance is \(6 \, \Omega\).
### Step 2: Write the Formula for Parallel Resistance
The formula for the equivalent resistance \(R_p\) of \(n\) resistors in parallel, each of resistance \(R\), is given by:
\[
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