Calculate the potential difference between points B and D of the network of resistance shown in figure

Explanation

Here, potential differences across ABC = potential differences across ADC = 12 V
Current in arm ABC,
`I_(1)=12/6+4 =1.2A`
pot. Diff. between A and B,
`V_(A) - V_(B)=I_(1) xx 6 =1.2 xx 6=7.2 V`
Current in arm ADC,
`I_(2)=12/8+12=0.6A`
pot. diff. across A and D,
`V_(A) - V_(D) = I_(2) xx 8 = 0.6 xx 8 =4.8 V`
`:. (V_(A) - V_(B)) - (V_(A) - V_(D))= 7.2 - 4.8 = 2.4 V`
or `V_(D) - V_(B) = 2.4 V`
`:. V_(B) - V_(A)= -2.4 V`
It shows that the point D is at higher potential than that of point B.