In the network shown in figure, the ring has zero resistance. Find the resistance between A and B.
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Here, three resistance each of value 6 R are in parallel and resistance R is in series between A and B. The equivalent circuit is shown in figure. The effective resistance of three resistances in parallel, `1/R = (1)/(6R) + (1)/(6R) +(1)/(6R) = (1)/(2R)` `:. R_(p) = 2R` Total resistance between A and B `= 2 R + R= 3R`
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