The current flowing through a conductor is 2 mA at 50V and 3 mA at 60V. Is it an ohmic or nonohmic conductor ?
Text Solution
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The resistance of first case, `R_(1)= (V_(1))/(I_(1))= (50V)/(2xx10^(-3)A)= 25,000 Omega` The resistance of second case, `R_(2)=(V_(2))/(I_(2))=(60V)/(3xx10^(-3)) = 20,000 Omega` As resistance changes with current, so the given conductor is nohn-ohmic.
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