Two square metal paltes are of same thichness and material. The side of B is twice that of A. Thses are connected in series, figure. If the resistance of A and B are denoted by `R_(A)` and `R_(B)` , find `R_(A)//R_(B)`.
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Let `l. d` length and thickness of square metal plate. Then `R_(A) = (rho l)/(A) = (rhol)/(lxxd) = rho/d and R_(B) = (rho xx 2l)/(2l xx d) = rho/d` `:. R_(A)/R_(B) = (rho//d)/(rho//d) = 1`
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