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Two identical slabs of given metal are j...

Two identical slabs of given metal are joined together in two different ways as shown in figure. What is the ratio of the resistance of these two combinations?

Text Solution

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Let `l` and A be the length and area of cross-section of the each of the two slabs. Then `R= rho l//A`
`R_(1) = (rho 2l)/A = 2R`
`R_(2) = (rho l)/(2A)= R/2`
`R_(1)/R_(2)=(2R)/(R//2) = 4 or R_(1) : R_(2)=4:1`
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