How will you join three resistances, each of `2 Omega` so that the effective resistance is `3 Omega` ?
Text Solution
Verified by Experts
Two resistances in parallel and the third resistance is connected in series with them.
Topper's Solved these Questions
CURRENT ELECTRICITY
PRADEEP|Exercise Conceptual Problems|3 Videos
CURRENT ELECTRICITY
PRADEEP|Exercise Very short Q/A|7 Videos
COMMUNICATION SYSTEMS
PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos
DUAL NATURE OF RADIATION AND MATTER
PRADEEP|Exercise Exercise|191 Videos
Similar Questions
Explore conceptually related problems
Show how would you join three resistors, each of resistance 9 Omega so that the equivalent resistance of the combination is (i) 13.5 Omega , (ii) 6 Omega ?
Show how you would connect three resistors, each of 6 Omega , so that the combination has a resistance of (a) 9 Omega , (b) 4 Omega .
Show with the help of diagrams, how you would connet three resistors each of resistance 6 Omega , so that the combination has resistance of (i) 9Omega (ii) 4Omega .
Show how you would connect thre resistors, each of resistance 6 Omega , so that the combination has a resistance of (i) 9 Omega (ii) 2 Omega .
Three resistors, each of 2 Omega , are connected together so that their total resistance is 3 Omega . Draw a diagram to show this arrangement and check it by calculation.
In the net work each resistance is 2 Omega . Find th effective resistance between A and B
PRADEEP-CURRENT ELECTRICITY-Problems for Practice (B)
