Two identical cells each of emf `epsilon`, having negligible internal reistance r, are connercted in parallel with each other across an external resistance R. What is the current through this resistance.
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Effective emf of the parallel combination of cells = emf of one cell `= epsilon` Total resistance of circuit = R, because cells are of negligible resistance. Therefore, current `I = ("effective emf")/("total resistance") = (epsilon)/(R)`
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