A uniform wire is cut into four segments. Each segment is twice as long as the earlier segment. If the shortest segment has a resistance of `2 Omega`, find the resistance of original wire.
Text Solution
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Let `l` be the length of shortest segment. Then lengths of four segments will be `l, 2 l, 4l, 8l`. Their corresponding resistance will be `R, 2 R, 4 R` and 8R. Given ` R =2 Omega`. Resistance of the original wire `1=R + 2 R +4R + 8R` `=15R = 15xx2 = 30 Omega`
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