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An electric current is passed through a circuit containing two wires of the same material connected in parallel. If the length and radii of the wires are in the ratio `2//3 and 4//3`, then find the ratio of the current passing through the wires

Text Solution

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`R_(1)/R_(2) = (rho l_(1)//pi r_(1)^(2))/(rho l_(2) // pi r_(2)^(2)) = (l_(1))/(l_(2)) xx r_(2)^(2)/r_(1)^(2) = 2/3 xx (3/4)^(2) = 3/8`
For wires connected in parllel
`V_(1) = V_(2) or I_(1)R_(1) = I_(2)R_(2)or I_(1)/I_(2)=R_(2)/R_(1) = 8/3`
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Knowledge Check

  • An electric current is passed through a circuit containing two wires of the same material connected in parallel. If the lengths and radii of the wire are in the ratio (4)/(3) and (2)/(3) , then the ratio of the currents passing through the wires will be

    A
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    `(3)/(1)`
    C
    `(4)/(3)`
    D
    `(3)/(4)`
  • An electric current is passed through a circuit containing two wires, of same material, connected in parallel. If the lengths and radii of the wires are in the ratio of 3:2 and 2:3, then the ratio of the current passing through the wire will be:

    A
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    B
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    D
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  • An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii are in the ratio of 4/3 and 2/3, then the ratio of the current passing through the wires will be

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