Effective resistance of arm `BE=(4xx4)/(4+4 )+ 4 = 6 Omega` It is in parallel with resistance `4 Omega` of arm CD. Their effective resistance `r' = (4 xx 6)/(4+6) = 2.4 Omega` Total resistance of circuit `=2.4 + 1.6 =4.0 Omega` Current `I= ("emf")/("total resistance") = 4/4 = 1A` Potential differnce between B and E `=1 xx 2.4 =2.4 V` `:.` Current `I_(1)=2.4/6 = 0.4A`
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