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Five 4 Omega resistance, 2 V battery and...

Five `4 Omega` resistance, 2 V battery and an ammeter are connected as shown in figure. Find the ammeter reading.

Text Solution

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The upper two `4 Omega` each and lower two `4 Omega` each are in parallel, their effective resistance R' is
`1/R' = 1/4 +1/4+1/4+1/4 = 4/4 = 1 or R' = 1 Omega`
The equivalent circuit is as shown in figure

Total resistance of circuit, `R =4+1 = 5 Omega`
Ammeter reading = current in circuit
`V/R=2/5 = 0.4 A`
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