Two cells of emfs 1.5 V and 2.0V internall resistance `1 Omega` and `2 Omega` are connected in parallel so as to send current in the same direction through an external resistance of `5 Omega`.
(i) Draw the circuit diagram. (ii) Using Kirchhoff's rules, calculate.
(a) current through each branch of the circuit (b) potential difference across the `5 Omega` resistance.

Explanation

To solve the problem step by step, we will first draw the circuit diagram, then apply Kirchhoff's rules to find the current through each branch and the potential difference across the external resistance.

### Step 1: Draw the Circuit Diagram
We have two cells connected in parallel. The first cell has an EMF of 1.5 V and an internal resistance of 1 Ω, while the second cell has an EMF of 2.0 V and an internal resistance of 2 Ω. Both cells are connected to an external resistance of 5 Ω.

**Circuit Diagram:**
```
+---[1.5V]---[1Ω]---+
...