The wheat stone bridge circuit have the resistance in various arms as shown in figure. Calculate the current through the galvanometer.
Text Solution
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In the closed loop ABDA , `100 I_(1) + 15 I_(g) - 60 I_(2)=0` or `20 I_(1) + 3 I_(g) - 12 I_(2)=0` In the closed loop BCDB , `10 (I_(1)- I_(g)) - 5 (I_(2) + I_(g)) - 15 I_(g)=0` `10 I_(1) - 30 I_(g) - 5 I_(2)=0` or `2 I_(1) - 6 I_(g) - I_(2)=0` In the closed loop ADCEA, `60 I_(2) + 5 (I_(2) + I_(g)) = 10` or `65 I_(2) + 5I_(g) = 10 or 13 I_(2) + I_(g) = 2` On solving (i), (ii) and (iii), we get `I_(g) = 4/821 A = 4.87 mA`
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