In meter bridge, the null points is found at a distance of 60.0 cm front end A. If now a resistance of `5 Omega` is connected in series with S, the null point occurs at 50 cm. Determine the values of R and S,
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In first case, `R/S=60/(100-60) = 3/2` In second case, `R/S+5 = 50/50 = 1 or R = S+5` From (i), `S+5/S =3/2 or 2S+10 = 3S` or `S=10 Omega` and `R= 10+5 =15 Omega`
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