A potentiometer wire of length 1.0 m has a resistance of 15 ohm. It is connected to a 5 V source in series with a resistance of `5 Omega`. Determine the emf of the primary cell which has a balance point at 60 cm.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the total resistance of the circuit
The total resistance in the circuit is the sum of the resistance of the potentiometer wire and the series resistance.

Given:
- Resistance of the potentiometer wire, \( R_{pot} = 15 \, \Omega \)
- Series resistance, \( R_{series} = 5 \, \Omega \)
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