The circuit shows in Fig . `6.33` shows the use of potentiometer to measure the internal resistance of a cell. (a) When the key is open, how does the balance point change, if the driver cell decreases ? (b) When the key is closed, how does the balance point change, if `R` is increased, keeping the current from the driver cell constant ?
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(i) When the key K is open and current from the driver cell increases, the potential gradient across the potentiometer wire increases. Due to it, the balance point shifts towards the end A of potentiometer wire. (ii) When the key k is closed and R is decreased, keeping the current from the driver cell constant, the terminal potential difference of the cell decrease. Due to it, the balance point shifts towards the end A of potentiometer wire.
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