Out of the two, a toaster of `1 kW` and an electric heater of `2 kW`, which has a greater resistance ?
Text Solution
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Here, V = 230 V, `P_(1) = 1 kW = 1000 W , P_(2) = 100 W` `R_(1) = V^(2)/P_(1) = (230)^(2)/1000 = 52.9 Omega` `R_(2) = V^(2)/P_(2) = (230)^(2)/100 = 529 Omega` As `R_(2) gt R_(1)`, so 100 W bulb has greater resistance.
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