The potential difference applied across a given resistor is altered so that the heat produced per second increases by a factor of 9. By what factor does the applied potential difference change ?
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As heat produced, `H = VI t = (V^(2))/R t` `:. H_(1) = (V_(1)^(2) t)/R and H_(2) = (V_(2)^(2)t)/R` `H_(1)/H_(2) = (V_(1)^(2))/(V_(2)^(2)) or V_(2)/V_(1) =sqrt((H_(2))/H_(1)) = sqrt((9H_(1))/H_(1)) = 3` or `V_(2) = 3 V_(1)` Hence potential difference changes by a factor of 3.
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