Two wires A and B of the same material and having same length, have their cross-sectional areas in the ratio `1:4`. what should be the ratio of heat produced in these wires when same voltage is applied across each ?
Text Solution
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` H = V^(2) t//R = V^(2) A t//rho l`. So `H prop A`, therefore `H_(1) //H_(2) = A_(1)//A_(2) = 1//4`
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