An electric kettle has two coils. When one of these is switched on, the water in the kettle boils in 6 minutes. When the other coil is switched on, the water boils in 3 minutes. If the two coils are connected in series, find the time taken to boil the water in the kettle.
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Heat produced, `H = V^(2)t//JR or R prop t` so `R_(1) prop 6` and `R_(2) prop 3`, therefore, `R_(1)//R_(2) =6//3 =2` or `R_(1) = 2 R_(2)` When coils are connected in series, then net resistance, `R' = R_(1) + R_(2) = 3 R_(2)` so `(R')/R_(2) = (t')/(3)` or `t'= (3R')/(R_(2)) = (3xx3R_(2))/R_(2) = 9` minutes
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