A battery of emf 10 v and internal resistane `3 Omega` is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistane of the resistors ? What is the terminal voltage of the battery when the circuit is closed ?
Text Solution
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Here, `epsilon = 10 V, r = 3 Omega , I = 0.5A , R = ? , V= ?` `I = epsilon/(R +r) or (R +r) = epsilon/I = 10/0.5 = 20 or R = 20 - 3 = 17 Omega` Terminal voltage, `V = IR = 0.5 xx 17 = 8.5 Omega`
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