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In the Wheatstone's bridge shown, P = 2 ...

In the Wheatstone's bridge shown, `P = 2 Omega, Q = 3 Omega, R = 6 Omega` and `S = 8 Omega`. In order to obtain balance, shunt resistance across S must be

Text Solution

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(i) Post office box and meterbridge are two electronical appliance head on the principal of wheastons bridge
(ii) Here `I = 39.5 cm, R= X, S= Y= 10 Omega`
As `S = ((100 - 1))/(I) xx R:. 10 = ((100 - 39.5)X)/(398) or X = (10 xx 39.5)/(605) = 6.53 Omega`
(b) As `X and Y` effect box interchange , length // and `(100 - 1)` of bridge are also changed `1 = 60.5` on and `(100 - 1) = 39.5 cm` Therefore shift in balace point of bridge wire
`= 60.5 - 39.5 = 21.0` toward right hand side
(iii) The post effect is box is practically in post and inlengh department to locate the stopping of telehone line .The broken telephone line will luch the ground and the resistance will be compleated through ground using post effect box , resistance `S` of broken line a decreaced .As resistance per unit length of line is known the length of broken line can be calculated .Therefore snapping of line as located
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