[" 70.Ethylene glycol (molar mass- "62" g mol "^(-1)" is a common automobile antifreeze.Calculate the "],[" freezing point of a solution containing "12.4" g of this substance in "100g" of water.Given "K" ,for "],[" water "=1.86Kkg" mol "^(-1)" ."]

Ethylene glycol ("molar mass"=62 g mol^(-1)) is a common automobile antyfreeze. Calculate the freezing point of a solution containing 12.4 g of this substance in 100 g of water. (Given K_(f) for water = 1.86 K kg mol^(-1))

The molality of a solution containing 0.1 mol of a substance in 100g of water is :

Ethylene glycol (molar mass = 62 g mol ^(-1)) is a common automobile antifreeze. Calculate the freezing point of a solution containing 12.4 of this substance in 100 g of water. Would it be advisable to keep this substance in the car radiator during summer? ( K_(f) for water= 1.86 k kg//mol) (K_(b) for water = 0.512 K kg//mol.)

Ethylene glycol (molar mass = 62gmol^-1) is a common automobile antifreeze. Calculate the freezing point of a solution containing 12.4g of this substance in 100g of water. Would it be advisable to keep this susbtance in the car radiators during summer? Given K_f for water = 1.86 K kg//mol K_b for water = 0.612 K kg//mol

Ethylene glycol (molar mass = 62gmol^-1) is a common automobile antifreeze. Calculate the freezing point of a solution containing 12.4 g of this substance in 100 g of water. Would it be advisable to keep this substance in car radiator during summer? (K_f for water=1.86Km^-1 and K_b for water=0.512Km^-1) .

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

The freezing point of a solution containing 0.1g of K_3[Fe(CN)_6] (Mol. Wt. 329) in 100 g of water ( K_f =1.86K kg mol^(−1) ) is: