Find the order of basic strength, (if `R=Me`).
(I) `R_(4)OH^(-), (II) R_(3)N`
(III) `R_(2)NH` , (IV) `RNH_(2)`

Options

A. `IgtIIIgtIVgtII`
B. `IVgtIIIgtIgtII`
C. `IIgtIVgtIIIgtI`
D. `IIgtIVgtIgtIII`

Explanation

To determine the order of basic strength among the given compounds when R = Me (methyl group), we will analyze the basicity of each compound based on the presence of lone pairs and the electron-donating effects of the alkyl groups.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- (I) \( R_4OH^- \) (which becomes \( (Me)_4OH^- \))
- (II) \( R_3N \) (which becomes \( (Me)_3N \))
- (III) \( R_2NH \) (which becomes \( (Me)_2NH \))
- (IV) \( RNH_2 \) (which becomes \( MeNH_2 \))

2. **Analyze Basic Strength**:
- Basic strength is influenced by the availability of lone pairs and the electron-donating effects of alkyl groups.
- Alkyl groups are electron-donating and increase the electron density on the nitrogen atom, enhancing its ability to donate the lone pair.

3. **Basicity of Each Compound**:
- **(I) \( (Me)_4OH^- \)**: This is a negatively charged species (alkoxide ion), which is highly basic due to the negative charge on oxygen. It will be the strongest base.
- **(II) \( (Me)_3N \)**: This compound has three methyl groups donating electron density to nitrogen. However, steric hindrance from the three bulky groups can reduce the basicity slightly compared to \( (Me)_2NH \).
- **(III) \( (Me)_2NH \)**: This compound has two methyl groups, which provide good electron donation without excessive steric hindrance. It will be more basic than \( (Me)NH_2 \).
- **(IV) \( MeNH_2 \)**: This compound has only one methyl group donating electron density, making it the least basic among the amines listed.

4. **Order of Basic Strength**:
- Based on the analysis, we can summarize the basic strength as follows:
1. \( (Me)_4OH^- \) (strongest)
2. \( (Me)_2NH \)
3. \( (Me)_3N \)
4. \( MeNH_2 \) (weakest)

5. **Final Order**:
- The final order of basic strength from strongest to weakest is:
\[ (Me)_4OH^- > (Me)_2NH > (Me)_3N > MeNH_2 \]