The correct basic strength order of the following anions is:

Options

A. `CH_(3)-overset(Θ)(CH_(2)) gt overset(Θ)(NH_(2)) gt CH_(2)=overset(Θ)(CH) gt CH-=overset(Θ)(C ) gt Hoverset(Θ)(O) gt overset(Θ)(F)`
B. `overset(Θ)(NH_(2)) gt CH_(3)-overset(Θ)(CH_(2)) gt CH_(2)=overset(Θ)(CH) gt CH-=overset(Θ)(C ) gt overset(Θ)(F) gt H overset(Θ)(O)`
C. `CH_(3)-overset(Θ)(C)H_(2) gt CH_(2)=overset(Θ)(CH) gt overset(Θ)(N)H_(2) gt CH-=overset(Θ)(C ) gt Hoverset(Θ)(O) gt overset(Θ)(F)`
D. `overset(Θ)(F) gt Hoverset(Θ)(O) gt CH-=overset(Θ)(C ) gt CH_(2)=overset(Θ)(C)H gt overset(Θ)(N)H_(2) gt CH_(3)-overset(Θ)(CH_(2))

Explanation

To determine the correct basic strength order of the given anions, we need to analyze the stability of each anion. The less stable the anion, the stronger the base it will be, as it will more readily donate its electrons. Here’s a step-by-step breakdown of the reasoning:

### Step 1: Identify the Anions
Let's assume the anions in question are:
1. \( F^- \) (Fluoride)
2. \( OH^- \) (Hydroxide)
3. \( CH_3^- \) (Methyl anion)
4. \( NH_2^- \) (Amide anion)
5. \( CH_2=CH^- \) (Vinyl anion)

### Step 2: Analyze the Stability of Each Anion
1. **Fluoride (\( F^- \))**:
- Highly electronegative, holds onto its electrons tightly.
- **Stability**: Very stable due to high electronegativity.
- **Basic strength**: Weak base.

2. **Hydroxide (\( OH^- \))**:
- Less electronegative than fluoride but still holds onto the negative charge fairly well.
- **Stability**: Moderately stable.
- **Basic strength**: Moderate base.

3. **Amide (\( NH_2^- \))**:
- Nitrogen is less electronegative than oxygen.
- **Stability**: Less stable than hydroxide, can donate its electrons more readily.
- **Basic strength**: Stronger base than hydroxide.

4. **Vinyl anion (\( CH_2=CH^- \))**:
- SP2 hybridized, less stable than amide but more stable than methyl.
- **Stability**: Less stable than \( NH_2^- \).
- **Basic strength**: Strong base.

5. **Methyl anion (\( CH_3^- \))**:
- SP3 hybridized, least electronegative, and least stable.
- **Stability**: Least stable, readily donates its electrons.
- **Basic strength**: Strongest base.

### Step 3: Order the Basic Strengths
Based on the stability analysis:
- **Weakest base**: \( F^- \) (most stable)
- **Next**: \( OH^- \)
- **Next**: \( NH_2^- \)
- **Next**: \( CH_2=CH^- \)
- **Strongest base**: \( CH_3^- \) (least stable)

### Final Order of Basic Strength
The order of basic strength from weakest to strongest is:
\[ F^- < OH^- < NH_2^- < CH_2=CH^- < CH_3^- \]

### Conclusion
Thus, the correct basic strength order of the anions is:
- **C part** (assuming C part corresponds to the order derived).