Maximum enolisation takes place in

Options

A. `CH_(3)COCH_(3)`
B. `CH_(2)COCH_(2)CHO`
C. `CH_(3)COCH_(2)COCH_(3)`
D.

Explanation

To determine which compound undergoes maximum enolization, we need to analyze the stability of the enol forms of the given compounds. Enolization is favored when the enol form is more stable, often due to factors like resonance and aromaticity.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We have four compounds to analyze for enolization:
- Compound 1: \( \text{CH}_3\text{C}=\text{O}\text{CH}_3 \)
- Compound 2: \( \text{CH}_3\text{CH}_2\text{C}=\text{O}\text{CH}_2\text{CHO} \)
- Compound 3: \( \text{CH}_3\text{CH}_3\text{C}=\text{O}\text{CH}_2\text{CO}\text{CH}_3 \)
- Compound 4: A compound with an aromatic system.

2. **Draw the Enol Forms**:
- For Compound 1: The enol form is \( \text{CH}_3\text{C(OH)=CH}_2 \).
- For Compound 2: The enol form is \( \text{OH} \text{CH}=\text{CH}\text{CHO} \).
- For Compound 3: The enol form can be drawn, but it does not have significant resonance.
- For Compound 4: The enol form will be aromatic, which is \( \text{OH} \text{C}=\text{C} \) with resonance.

3. **Analyze Stability**:
- **Compound 1**: The enol form is not stabilized by resonance.
- **Compound 2**: The enol form has some resonance but is not aromatic.
- **Compound 3**: The enol form lacks significant resonance stabilization.
- **Compound 4**: The enol form is aromatic, which greatly increases its stability due to resonance.

4. **Conclusion**:
The enol form of Compound 4 is the most stable due to its aromaticity and resonance stabilization. Therefore, maximum enolization occurs in Compound 4.

### Final Answer:
Maximum enolization takes place in Compound 4.