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In Carius method, 0.099 g organic compo...

In Carius method, `0.099 g ` organic compound gave `0.287 g AgCl.` The percentage of chlorine in the compound will be

A

`28.6`

B

`71.7`

C

`35.4`

D

`64.2`

Text Solution

Verified by Experts

The correct Answer is:
B
`%` of chlorine`=(35.5)/(143.5)xx(Mass of AgCl)/(Mass of su bta n c e)xx100`
`(35.5)/(143.5)xx(0.287)/(0.099)xx100=71.71%`
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