Victor Meyer's method, `0.2 g` of an organic substance displaced `56 ml` of air at `STP`. The molecular weigth of the compound of

Options

A. 56
B. 112
C. 80
D. 28

Answer

C

Explanation

Molecular mass
`underset(sp^(3))(overset(6)(C)H_(3))-underset(sp^(2))(overset(5)(C)H_(3))=underset(sp^(2))(overset(4)(C)H)-underset(sp^(3))(overset(3)(C)H)-underset(sp)(overset(2)(C))-=underset(sp)(overset(1)(C)H)`
`=(0.2)/(56)xx22400=80`