An organic compound containing `C,H` and `N` have the percentage `40,13.33` and `46.67` respectively. Its empirical formula may be`:`

Options

A. `C_(2)H_(7)N`
B. `C_(2)H_(7)N_(2)`
C. `CH_(4)N`
D. `CH_(5)N`

Answer

c

Explanation

`%` Relative no. of atoms Simple ratio
`C" "40" "(40)/(12)=3.333" "(3.33)/(3.33)=1`
`H" "13.33" "(13.33)/(1)=13.33" "(13.33)/(3.33)=4`
`N" "46.67" "(46.67)/(14)=3.33" "(3.33)/(3.33)=1`
`:.` Empirical formula is `CH_(4)N.`