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In the hydrocarbon, underset(6)(C)H(3)...

In the hydrocarbon,
`underset(6)(C)H_(3)-underset(5)(C)H=underset(4)(C)H-underset(3)(C)H_(2)-underset(2)(C)-=underset(1)(C)H`
the state of hybrization of carbon `1,3` and `5` are in the following sequence

A

`sp,sp^(3),sp^(2)`

B

`sp,sp^(2),sp^(3)`

C

`sp^(3),sp^(2),sp`

D

`sp^(2),sp,sp^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(sp^(3))(overset(6)(C)H_(3))-underset(sp^(2))(overset(5)(C)H_(3))=underset(sp^(2))(overset(4)(C)H)-underset(sp^(3))(overset(3)(C)H)-underset(sp)(overset(2)(C)H)-=underset(sp)(overset(1)(C)H)`
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In the hydrocarbon underset(6)(C)H_(3)-underset(5)(C)H=underset(4)(C)H-underset(3)(C)H_(2)-underset(2)(C)-= underset(1)(C)H The state of hybridization of carbons 1,3 and 5 are in the following sequence

CH_(3)-underset(O)underset(||)(C)-NHC_(6)H_(5)

H_(5)C_(2)Ounderset(O)underset(||)(C)-CH_(2)CH_(2)underset(O)underset(||)(C)-OC_(2)H_(5)

The correct IUPAC name CH_(3)-underset(CH_(3))underset(|)(C)=underset(C_(2)H_(5))underset(|)(C)-CH_(3)

C_(6)H_(5)-CH=underset(CHO)underset(|)C-C_(6)H_(5)

The correct IUPAC name of CH_(3)-underset(CH_(3))underset(|)(C)=underset(C_(2)H_(5))underset(|)(CH)

Consider the compound given below Hunderset(1)(C)-=underset(2)(C)-underset(3)(C)H=underset(4)(C)H-underset(5)(C)H_(3) The hybridisation of C_(1),C_(3) and C_(5) are respectively.

The IUPAC name of : H_(5)C_(2)-underset(CHO)underset(|)(C)H-underset(CH_(3))underset(|)(C)H - C_(2)H_(5) is

IUPAC name of : CH_(3)-CH_(2)-underset(O)underset(||)(C)-underset(CH_(3))underset(|)(CH)-underset(O)underset(||)(C)-C_(2)H_(5)

A2Z-CLASSIFICTION, PURIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS-AIPMT/NEET/AIIMS Problem
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