Empirical formula of a compound is `CH_(2)O` and its vapour density is 30. Molecular formula of the compound is

Options

A. `C_(2)H_(6)O_(3)`
B. `C_(2)H_(4)O_(2)`
C. `C_(2)H_(4)O`
D. `CH_(2)O`

Answer

B

Explanation

Empirical formula `=CH_(2)O`
Empirical formula mass `=12+2+16=30`
Mol. Mass `2xxV.D.=2xx30=60`
`n=(Mol. mass)/("Emperical mass")=(60)/(32)=2`
Molecular formula`=(` emperical formula`)_(n)`
`=(CH_(2)O)_(2)=C_(2)H_(4)O_(2)`